Two solid components P and Q dissociate at a certain temperature as follows.P(S)⇌A(g)+2B(g)KP=9×10-3 atm3Q(s)⇌2B(g)+C(g)KP=4.5×10-3 atm3If both solids P and Q were kept in a container at same temperature and allowed to decompose. The equilibrium pressure in the container is

When both equilibria attained together the partial pressure of common product will remain same. During P(s)⇌Ag)+2B(g) equilibrium if PA=xatm During Q(s)⇌2B(g)+2C(g) equilibrium if PC=yatm The partial pressure of BPB=2x+2y∴9×10-3 atm 3=PAPB2 9×10-3 atm 3=(x)(2x+2y)2→1 4.5×10-3atm3=PB2PC 4.5×10-3atm3=(2x+2y)2(y)→2 12 gives x=2y By solving equations  x = 0.1 atm                                        y = 0.05 atm ∴ Equilibrium pressure =PA+PB+PC                                          =x+(2x+2y)+y=0.45atm