Q.

Two volatile liquids A and B are mixed in the mole ratio 3 : 2 to form an ideal solution. Vapour pressure of pure liquids A and B is 600 mm Hg and 300 mm Hg respectively. Mole fraction of B in vapour phase is

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0.66

0.33

0.25

0.4

answer is C.

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Detailed Solution

Mole fraction in liquid mixtureXA=35 ; XB=25Given pAo=600 mm ; pBo=300 mmAccording to Raoult's law Ptotal=pAoXA+pBoXBPtotal=60035+30025Ptotal=360+120mmIn vapour phase, applying Dalton's lawpB=ptotal×yByB=pBptotalyB=120480yB=0.25

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