Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

The type of bonds present in the final product formed in the reaction of excess ethyl chloride with ammonia in a sealed tube at 373 K is/are

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

Covalent bonds only

b

Covalent and ionic bonds only

c

Ionic, covalent and dative bonds

d

Ionic and dative bonds only

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

4C2H5Cl→-3HClNH3C2H54N+Cl- ; Tetra ethyl ammonium chlorideIonic bond between C2H54N+ and Cl- ;Dative bond between C2H53N. . and C2H5Cl, nitrogen donates its lp to ethyl carbocation ;Covalent bonds between C-H, N-H etc.
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring