The type of hybrid orbitals used by the chlorine atom in ClO2− is
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a
sp3
b
sp2
c
sp
d
None of these
answer is A.
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Detailed Solution
H=12(V+M−C+A) where H=No. of orbitalsinvolved in hybridisation (viz. 2, 3, 4, 5, 6) and hence nature of hybridisation (viz. sp2⋅sp3,sp3d,sp3d2 can be ascertained. V = No. of electrons in valence shell of the central atom: M = No. of monovalent atoms, C = charge on cation. A = Charge on anion, ⇒H=12(7+1)=4 or sp3 hybridisation as 4 orbitals are involved.