92U238 emits 8α-particles and 6β-particles. The n/p ratio in the product nucleu:E is

8 α-particle emission decreases the atomic mass number by8 × 4 =32.Therefore, atomic mass number of product nucleus is 238 - 32 = 206.6 β-particles and 8 o-particles emission decreases the atomic number by 8 × 2 - 6 × 1 = 10. Therefore, atomic number of product nucleus -- 92 - 10 = 82..'.number of neutrons in nucleus = 206 - 82 = 124.