UF6(mol, wt., 350gmol) was filled in an evacuated bulb of 0.15 m3 size at 27°C and 2.4 x 10-2 atm. pressure. Calculate the mass of UF6 in the bulb if R = 0.082 L atm K- mol-
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answer is 51.16.
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Detailed Solution
wt. of UF6=?, mol. wt. of UF6=350gmol−.∴ no. of mol. of UF6=n=w(w) Mol. wt. =w350gmol−P=2.4×10−2atm;V=0.15m3;T=27+273=300KPV=WMRT(gas equation);∵1L=10−3m3∴W=350gmol−×2.4×10−2atm×0.15m30.0821×10−3m3atmK−mol−×300K=51.16g