The uncertainty in position and velocity of the particle are 0.1 nm and 5.27 × 10−27 ms−1 respectively. Then the mass of the particle is : h=6.625 × 10−34 Js
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a
200 g
b
300 g
c
100 g
d
1000 g
answer is C.
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Detailed Solution
Δx= 0.1 × 10−9 m. ΔV=5.27 × 10−27 ms−1.∴ Δx × mΔV =h4π∴ 0.1 × 10−9 m × 5.27 × 10−27 =0.527 × 10−34.∴ m=0.1 kg. = 100 g.