First slide

Work

Question

Under isothermal conditions at 300K, a gas is expanded from 0.2 lit to 0.65 lit against a constant external pressure of 4 bar. Work done during the process is (1lit bar = 100J)

Moderate

Solution

$\begin{array}{l} w_{irr} = - P_{ext} (V_{f} - V_{i}) \\ = - 4 (0 .65 - 0 .2) \\ \begin{array}{l} = - 4 (0 .45) \\ \begin{array}{l} = - 1 .8 litbar \\ W_{irr} = - 1 .8 (100) \\ = - 180 J \end{array} \end{array} \end{array}$

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