First slide

Conductivity , Molar conductivity and Equivalent Conductivity

Question

For unimolar solution of uni-univalent electrolyte, the correct relation between equivalent conductance ( $mho . {cm}^{2} . g {eq}^{- 1}$ ) and specific conductance ( $mho . {cm}^{- 1}$ ) is

Easy

A

$\land eq = \frac{K}{1000}$
B

$\land eq = 1000 K$
C

$\land eq = \frac{1000}{K}$
D

$\land eq = K$

Solution

$\land eq = K \times \frac{1000}{N} (in CGS)$
$\land eq = 1000 K$

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