Unlike PbCl4, PI4 and PBr4 are not found because

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bromine and iodine are more electronegative than chlorine.

iodine and bromine are smaller in size.

larger iodine and bromine are able to reduce Pb4+ to Pb2+ or Pb.

the statement is incorrect

answer is C.

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Detailed Solution

Pb4+ has higher polarizing power and Br- and I- being larger in size can easily give the electrons to Pb4+, i.e., as compared to Cl-, Br- and I- are good reducing agents.

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