The unstable nucleus $$82212Pb$$ decays with β$$-particle$$ emission, having a $$half-life$$ of $$10$$ h. From this it follows that theA : mass number of the product is $$212B$$ : atomic number of the product is $$81C$$ : fraction of the original isotope remaining after $$20$$ h is $$14D$$ : product nucleus formed belongs to same groupSelect the correct alternate.

Question

The unstable nucleus $$82212Pb$$ decays with β$$-particle$$ emission, having a $$half-life$$ of $$10$$ h. From this it follows that theA : mass number of the product is $$212B$$ : atomic number of the product is $$81C$$ : fraction of the original isotope remaining after $$20$$ h is $$14D$$ : product nucleus formed belongs to same groupSelect the correct alternate.

Infinity Learn · Accepted Answer

.once beta particle is emitted atomic number increases by one unit, therefore its group also changes in this case

Unlock the full solution & master the concept.

Ready to Test Your Skills?

speak to our academic counsellor

free study material