‘V’ litres of 0.5 M KMnO4 can completely oxidise 2 litres of 0.5 M oxalic acid in acidic medium. The value of ‘V’ is

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0.4

0.8

1.6

2.4

answer is B.

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Detailed Solution

V1N1(KMnO4)=V2N2(H2C2O4) ;V1(n1)M1(KMnO4)=V2(n2)M2(H2C2O4) ;V(5)0.5 (KMnO4)=2(2)0.5(H2C2O4) ; V= 0.8 litres ;

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