‘V’ litres of 0.2 M KMnO4 can completely oxidise 5 litres of 0.4 M oxalic acid in acidic medium. The value of ‘V’ is
4
8
1.6
2.4
V1N1(KMnO4)=V2N2(H2C2O4) ;
V1(n1)M1(KMnO4)=V2(n2)M2(H2C2O4) ;
V(5)0.2 (KMnO4)=5(2)0.4(H2C2O4) ;
V= 4 litres ;