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Q.

The value of ∆E when the system absorbs 1000 kJ of heat and does 650 kJ of work on the surroundings is

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answer is 350.

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Detailed Solution

ΔE=q+WΔE=1000−650=350kJ(work done on the system is positive, work done on the surrounding is thus negative).
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The value of ∆E when the system absorbs 1000 kJ of heat and does 650 kJ of work on the surroundings is