The value of enthalpy change ∆H for the reactionC2H5OHl + 3O2g  →  2CO2g+3H2Olat 270C is -1366.5 kJ mol-1. The value of internal energy change for the above reaction at this temperature will be

Relation between ∆H (enthalpy change) and ∆E (internal energy change) is∆H=∆E + ∆ngRTwhere ∆ng = (moles of gaseous products) - (moles of gaseous reactants)For the given reaction,∆ng=2-3=-1 ⇒  -1366.5 = ∆E-1 × 8.314 × 10-3 × 300 ∴    ∆E=-1364.0 kJ mol-1