The value of equilibrium constant of the reaction, HIg ⇌ H2(g) + 12 I2(g) is 8.0. The equilibrium constant of the reactionH2(g) + I2(g) ⇌ 2HIg will be

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164

116

answer is A.

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Detailed Solution

For HI ⇌ 12 H2 + 12 I2 ; Kc1=8Reverse given eqn. and multiply by 2.∴ For H2 + I2 ⇌ 2HI; KC2 = 1KC12= 182 = 164

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