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Q.

The value of equilibrium constant of the reaction, HIg  ⇌  H2(g)  +  12 I2(g) is 8.0. The equilibrium constant of the reactionH2(g) + I2(g)   ⇌  2HIg  will be

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a

164

b

16

c

18

d

116

answer is A.

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Detailed Solution

For  HI  ⇌ 12 H2  +  12  I2 ;  Kc1=8Reverse given eqn. and multiply by 2.∴    For    H2 + I2   ⇌  2HI;    KC2 = 1KC12= 182 = 164
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