The value of four quantum numbers for the last electron of atom of element 'P' are $$n=7$$,$$l=1$$,$$m=$$±$$1$$ or $$s=+12$$,−$$12$$ and value of spin magnetic moment for element 'P' is zero. The element has two isotopes, zAP and zBP. Given: B $$-$$ A $$=$$ B $$-$$ $$2Z$$ $$=$$ $$18$$, where A and B are atomic masses and Z is atomic number.Select incorrect statement based upon above information

Question

The value of four quantum numbers for the last electron of atom of element 'P' are $$n=7$$,$$l=1$$,$$m=$$±$$1$$ or $$s=+12$$,−$$12$$ and value of spin magnetic moment for element 'P' is zero. The element has two isotopes,  zAP and zBP. Given: B $$-$$ A $$=$$ B $$-$$ $$2Z$$ $$=$$ $$18$$, where A and B are atomic masses and Z is atomic number.Select incorrect statement based upon above information

Infinity Learn · Accepted Answer

For last e−of element ' P′⇒$$n=7$$,$$l=1$$,$$m=+1$$ and $$s=$$ $$+12$$ or −$$12$$, shows that last e−is present in " $$7p$$ " sub shell and spin magnetic moment is zero, so there is no unpaired $$e-1s$$.Hence outer electronic configuration of "P' $$-$$ $$7P6$$ ; belongs to $$18th$$ group with Z $$=$$ $$118$$.Correct (2)'P' is nobel gas and is not representative element according to Bohr's classification. (3) $$Z=118$$,B−$$2Z=18$$, so $$B=254$$ and B−$$A=18$$, so $$A=236$$.  (4) $$90$$ th e−goes to $$5f$$ subshell so four quantum numbers are, $$n=5$$,$$l=3$$,$$m=$$−$$2$$ and $$s=$$−$$12$$ or $$+12$$

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