The value of four quantum numbers for the last electron of atom of element 'P' are n=7,l=1,m=±1 or s=+12,−12 and value of spin magnetic moment for element 'P' is zero. The element has two isotopes,  zAP and zBP. Given: B - A = B - 2Z = 18, where A and B are atomic masses and Z is atomic number.Select incorrect statement based upon above information

For last e−of element ' P′⇒n=7,l=1,m=+1 and s= +12 or −12, shows that last e−is present in " 7p " sub shell and spin magnetic moment is zero, so there is no unpaired e-1s.Hence outer electronic configuration of "P' - 7P6 ; belongs to 18th group with Z = 118.Correct (2)'P' is nobel gas and is not representative element according to Bohr's classification. (3) Z=118,B−2Z=18, so B=254 and B−A=18, so A=236.  (4) 90 th e−goes to 5f subshell so four quantum numbers are, n=5,l=3,m=−2 and s=−12 or +12