The value of ΔGf0 of gaseous mercury from liquid mercury is 31kJ/mol . The total external pressure where mercury starts boiling if temperature kept constant at 25°C is( take gas constant as 8.3 J·K-1·mol-1 )

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10-12.5

10-8.4

10-3.12

10-5.44

answer is D.

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Detailed Solution

ΔG0=-2.303RTlogKP Hg(l)⇌Hg(g) ∴KP= Pressure of mercury vapor 31000 J.mole-1=-2.303×8.3 J·K-1·mole-1×298 K×log(P) P=10-5.44

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