The value of Kc is 64 at 800K for the reaction N2(g)+3H2(g)⇌2NH3(g) . The value  of Kc for the following reaction is: NH3(g)⇌12N2(g)+32H2(g)

Given  N2(g)+3H2(g)⇌2NH3(g)  KC=64If we reverse the reaction then equilibrium constant becomes 1Kc⇒2NH3(g)⇌N2(g)+3H2(g)   KC1 =164If the entire reaction is multiplied by ‘X’ then the equilibrium constant becomes 1KxNH3(g)⇌12N2(g)+32H2(g)Keq=164=18