The value of K for the following reaction is 4, at 25°C CH3COOH(l)+C2H5OH(l)→CH3COOC2H5(l)+H2O(I)In this reaction a written spontaneous at 25°C? [R = 8.314 JK-1]

We know thatΔG∘=−2.303RT logKSubstituting the given data in the formula, we getΔG∘=−2.303×8.314×298×log⁡4ΔG∘=−2.303×8.314×298×2×0.3010ΔG∘=−3.435kJmol−1Since ∆G° is negative, the process is spontaneous.