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The value of n in the following equation if balanced 2Cr3+ + nFe3+ + 7H2O

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a

2

b

3

c

7

d

6

answer is D.

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Detailed Solution

n-factor (oxidation state) 2Cr change is 6, then it multiplied with Fe, now we getCr2O7-2 +14 H++6Fe+2→2Cr+3 +6Fe+3 +7H2O

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