The value of n in the molecular formula $$BenAl2Si6O18$$ is:

$$BenAl2Si6O18$$∵n×$$($$−$$2)+2$$×$$(+3)+6$$×$$(+4)+18($$−$$2)=0$$∴ $$n=+3$$

Classical idea of redox reactions

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Question

The value of n in the molecular formula Be_nAl₂Si₆O₁₈ is:

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Solution

${Be}_{n} {Al}_{2} {Si}_{6} O_{18}$
$∵ n \times (- 2) + 2 \times (+ 3) + 6 \times (+ 4) + 18 (- 2) = 0$
$∴ n = + 3$

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