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Q.

The van der Waals' constant ' b' of a gas is 4π×10−4L/mol. How near can the centres of the two molecules approach each other?  [Use: NA=6×1023 ]

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a

10-7 m

b

10-10 m

c

5 x 10-11 m

d

5 x 10-9 m

answer is B.

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Detailed Solution

b=4×43×πr3×NA4×π×10−4×1000 =4×43×π×r3×6×1023r=5×10−9cmDistance of closest approach = 2r=10−8cm  or 10−10m
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