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The van der Waal's constants for a gas are a=3.6 atmL2mol−2,b=0.6 Lmol−1. If R=0.08 L atm K-1mol-1 and the Boyle's temperature (K) is TB of this gas, then what is the value of TB15?

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answer is 5.

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Detailed Solution

TB=aRb=3.60.08×0.6=75K,7515=5K

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