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Q.

The vander Waal's constants for a = 3.6 atm L2mol-2 ,b = 0.6 L mol-1. If R = 0.08 L atm K-1 mol-1. The Boyle's temperature (TB) of this gas is :

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a

75 K

b

100 K

c

150 K

d

200 K

answer is A.

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Detailed Solution

TB=aRb=3.60.08×0.6=75K

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