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Q.

vander Waal's constants a and b for CO2 gas are 3.592 atm L2mol-2 and 0.0427 L  mol−2 respectively. The Boyle's temperature for the gas will be:

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a

84.12K

b

373K

c

1000K

d

1024.6K

answer is D.

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Detailed Solution

Boyle's temperature,Tb=abR     =3.592atmL2mol−20.0427Lmol−×0.0821LatmK−mol−or  Tb=1024.6K ∵ R=0.0821LatmK−mol
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