First slide

Abnormal Colligative properties ,Vant-Hoff's factor

Question

The Van’tHoff factor for 0.1 M Ba(NO₃)₂ solution is 2.74. The degree of dissociation is

Moderate

A

91.3%
B

87%
C

100%
D

74%

Solution

$\large Ba(NO_3)_2\rightleftharpoons Ba^{+2}+2NO_3^-$
n=3
i=2.74
i= 1+ $α$ (n-1)
2.74 = 1+ $α$ (3-1)=1+2 $α$
2 $α$ =2.74-1=1.74
$α$ = $\frac{1.74}{2} = 0.87$
Degree of ionization of 0.1M Ba(NO₃)₂ = 0.87
percentage of ionization of 0.1M Ba(NO₃)₂ = 87%

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