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The van't Hoff factor of BaCl2 at 0.01 M concentration is 1.98. The percentage of dissociation of BaCl2 at this concentration is
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a
49
b
69
c
89
d
98
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Correct option is A
BaCl2⇌Ba2++2Cl- Initial 0.01 M 0 0 At equil. (0.01-x) xM 2xM i=0.01-x+x+2x0.01=0.01+2x0.01=1.98 ⇒ x=0.0049 Percentage of α=x0.01×100=0.0049×1000.01=49%Similar Questions
The values of van't Hoff factors for KCl, NaCl and K2SO4 respectively are
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