Q.

The van't Hoff factor of BaCl2 at 0.01 M concentration is 1.98. The percentage of dissociation of BaCl2 at this concentration is

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a

49

b

69

c

89

d

98

answer is A.

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Detailed Solution

BaCl2⇌Ba2++2Cl- Initial         0.01 M            0       0 At equil.     (0.01-x)     xM     2xM                   i=0.01-x+x+2x0.01=0.01+2x0.01=1.98 ⇒    x=0.0049 Percentage of α=x0.01×100=0.0049×1000.01=49%
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