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Q.

Van't Hoff factor of 10% dissociated Potassium ferrocyanide solution is

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a

1.1

b

1.3

c

1.4

d

1.2

answer is C.

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Detailed Solution

For electrolytes like….A2B3(tri-bivalent), A3B2(bi-trivalent), A4B(uni-tetravalent)…..n=5                     Van't Hoff factor, i = 1-α+nα ;    when n= 5                    Van't Hoff factor, i = 1+4α ; Ex….Al2(SO4)3, Ca3(PO4)2, K4[Fe(CN)6], [Co(NH3)6]2(SO4)3α= Degree of ionization  (or) dissociation ;Ex ; For 5% ionized electrolyte  α=5100= 0.05 ;0.1, 0.15, 0.2, 0.25, 0.3…..for 10%, 15%, 20%, 25%, 30% ionized electrolyteα for x% electrolyte = x100; a) i= 1.2….5% ionized  b) i= 1.4…..10% ionized c) i=1.6….15% ionized d) i= 1.8…..20% ionized…..Hint: For every 5% increase in ionization i.e for every 0.05 units increase in 'α' value ‘i’ increases by 0.2 units ;
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