The van't Hoff factor (i) for a dilute aqueous solution of the strong electrolyte barium hydroxide is
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a
0
b
1
c
2
d
3
answer is D.
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Detailed Solution
Being a strong electrolyte, Ba(OH)2 undergoes 100 % dissociation in a dilute aqueous solution,Ba(OH)2(aq)⟶Ba(aq)2++2OH(aq)-Thus, van't Hoff factor i = 3