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An Intiative by Sri Chaitanya
a
logKp2Kp1=ΔH∘2.303RT1−T2T1T2
b
logKp2Kp1=ΔH∘2.303RT2−T1T1T2
c
logKp2Kp1=ΔH∘2.303RT1T2T1-T2
d
logKp2Kp1=∆H°RT1-T2T1T2
answer is B.
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