The vapour density of a mixture containing NO2 and N2O4 is 38.3 at 27°C. Calculate the moles of NO2 in 500 g of the mixture.

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answer is 2.19.

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Detailed Solution

mol. mass of mixture = 2 × 32.3 = 76.6 No. of moles in 500g of mixture =50076.6Let ag of NO2 is present in mixture.Moles of NO2 + Moles of N2O4 = Moles of mixture.a46+500−a76.6=50076.6 or a=100.52g Moles of NO2 in mixture =100.5246=2.19

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