The vapour density of N2O4 at a certain temperature is 30.67. The percentage of dissociation of N2O4 at given temperature is ___?

N2O4⇌2NO2 Initially                  1mole      0                               -x            +2x  at equilibrium     1-x         2xAccording to law of conservation of mass, mass of equilibrium mixture is 92 grams.Mass of 1mole of equilibrium mixture =921+x921+x=2×30.67x=0.5 So, N2O4 has been 50% dissociated at given temperature or you can use where D = theoritical vapour density (GMW/2), d= experimentally determined vapour density, n= no of product ions or molecules formed from one molecule of reactant