Q.

The vapour density of a volatile chloride of a metal is 59.5 and the equivalent mass of the metal is 24. The atomic mass of the element will be

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a

96

b

48

c

24

d

12

answer is B.

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Detailed Solution

MW of metal chloride = 2(59.5)=119EW of metal = 24EW of Chloride ion = 35.5Ew of metal chloride = (24 + 35.5) = 59.5valency = 119/59.5=2AW = EW x Valency      = 24 x 2 = 48
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