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Q.

The vapour pressure of benzene at 80oC is lowered by 10 mm by dissolving 2 g of a non-volatile substance in 78 g of benzene. The vapour pressure of pure benzene at 80oC is 750 mm. The molecular weight of the substance will be:

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a

15

b

150

c

1500

d

148

answer is D.

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Detailed Solution

P0−PsPs=w×Mm×W10(750−10)=2×78m×78 m=148NOTE: [m comes 150 if formula P0−PsPo=w×Mm×W is used. But this is only for dilute solutions.]
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