Vapour pressure of CCl4 at 25oC is 143 mmHg ,0.05 g of a non-volatile solute (mol. wt. = 65) is dissolved in 100 ml CCl4. Find the vapour pressure of the solution (Density of CCl4=1.58 g/cm3)

Po-PsPo=w×MmW=143-1.03=141.97 mm                                                                   ORPo-PSPo= nBnA nB= 0.0565=0.00076wCCl4 = V×d = 100×1.58=158 nA = 158154Po-PSPo= 0.0565×154158Po-PSPo=0.007 143-PS=0.007×143 143 -PS =1.001 PS=143-1.001=141.99mm of Hg