Vapour pressure of chloroform (CHCI3) and dichloromethane (CH2Cl2) at $$25o$$ C are $$200$$ mm of Hg and $$41.5$$ mm of Hg respectively. Vapour pressure of the solution obtained by mixing $$25.5$$ g of $$CHCl3$$ and $$40$$ g of $$CH2Cl2$$ at the same temperature will be (Molecular$$ mass of $$CHCI3$$ $$=$$ $$119.5$$ u and molecular mass of $$CH2Cl2$$ $$-$$ $$85$$ $$u)

Question

Vapour pressure of chloroform (CHCI3) and dichloromethane (CH2Cl2) at $$25o$$ C are $$200$$ mm of Hg and $$41.5$$ mm of Hg respectively. Vapour pressure of the solution obtained by mixing $$25.5$$ g of $$CHCl3$$ and $$40$$ g of $$CH2Cl2$$ at the same temperature will be (Molecular$$ mass of $$CHCI3$$ $$=$$ $$119.5$$ u and molecular mass of $$CH2Cl2$$ $$-$$ $$85$$ $$u)

Infinity Learn · Accepted Answer

Number of moles of $$CHCI3$$,                $$nA=wM=25.5119.5=0.213Number$$ of moles of $$CH2Cl2$$               $$nB=4085=0.47Mole$$ fraction of $$CHCI3$$,             $$xA=nAnA+nB=0.2130.683=0.31Mole$$ fraction of $$CH2Cl2$$              $$xB=1$$−$$xA=1$$−$$0.31=0.69ptotal$$ $$=pAxA+pBxB$$         $$=200$$×$$0.31+41.5$$×$$0.693$$         $$=62+28.63=90.63mmHg$$

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