Q.

Vapour pressure of liquid ‘A’ is 400mm Hg and liquid ‘B’ is 600mm Hg. If the V.P of the mixture containing 1:1 mole ratio of ‘A’ and ‘B’ is 504 mm Hg then the incorrect statement is

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answer is 4.

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Detailed Solution

PA0 = 400mm ; PB0 = 600mm;XA=XB=0.5; Ptotal=4000.5+6000.5=500 mm Hg;But the VP of the mixture is greater(504 mm Hg) than expected from Raoults law. It shows positive deviations from Raoult’s law∴ ΔHmix > 0ΔVmix > 0Boiling point of mixture is lesser than its components;∆Gmix< 0…..for ideal and also for non ideal solutions;

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