Q.

The vapour pressure of mercury is 0.002 mm Hg at 27∘C.Kc for the process Hg(l)⇌Hg(g) is

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a

0.002

b

8.12×10−5

c

6.48×10−5

d

1.068×10−7

answer is D.

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Detailed Solution

Kc=[Hg(g)];P=CRT C=0.002760×1(0.0821×300) =1.068×10-7M
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