Q.
The vapour pressure of mercury is 0.002 mm Hg at 27∘C.Kc for the process Hg(l)⇌Hg(g) is
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a
0.002
b
8.12×10−5
c
6.48×10−5
d
1.068×10−7
answer is D.
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Detailed Solution
Kc=[Hg(g)];P=CRT C=0.002760×1(0.0821×300) =1.068×10-7M
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