The vapour pressure of pure liquid solvent A is 0.80 atm. When a non-volatile substance B is added to the solvent, its vapour pressure drops to 0.60 atm. Mole fraction of the component B in the solution is:
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a
0.50
b
0.25
c
0.75
d
0.40
answer is B.
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Detailed Solution
Acc. to R.L. V.P.⇒ΔPP0=XBXB=0.80-0.600.80=0.200.80=0.25