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Q.

The vapour pressure of pure liquid solvent A is 0.80 atm. When a non-volatile substance B is added to the solvent, its vapour pressure drops to 0.60 atm. Mole fraction of the component B in the solution is:

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a

0.50

b

0.25

c

0.75

d

0.40

answer is B.

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Detailed Solution

Acc. to R.L. V.P.⇒ΔPP0=XBXB=0.80-0.600.80=0.200.80=0.25
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