The vapour pressure of pure liquid A is 10 torr and at the same temperature when 1 g of B solid is dissolved in 20 g of A, its vapour pressure is reduced to 9.0 torr. If the Molecular mass of A is 200 amu, then the molecular mass of B is

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100 amu

90 amu

75 amu

120 amu

answer is B.

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Detailed Solution

10-910=1x1x+20200110=1x1x+110=10x+10⇒x=90

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