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Q.

Vapour pressure of pure liquids A & B are 180 mm and 540 mm respectively. Equimolar mixture of A & B is prepared which behaves like an ideal solution. Molefraction of ‘B’ in vapour phase will be

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answer is 3.

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Detailed Solution

Ptot = pA0XA+pB0XBGiven XA = XB = 0.5Ptot = 0.5180+0.5540       = 90+270mm       = 360 mmIn Vapour phasePB = Ptot×yB;     yB = PBPtot      = 0.5540360     = 34       = 0.75
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