Questions
Vapour pressure of pure A is 70 mm of Hg at 25oC.It forms an ideal solution with 'B' in which mole fraction of A is 0.8. If the vapour pressure of the solution is 84 mm of Hg at 25oC the vapour pressure of pure B at 25oC is
detailed solution
Correct option is C
Given,p∘A=70mmHg xA=0.8∴ xB=(1−0.8)=0.2 and p=84mmHgAccording to Raoult's law, p=pA∘xA+pB∘xB84=0.8×70+0.2×pB∘pB∘=280.2=140mmHgTalk to our academic expert!
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At 40oC, the vapour pressure of pure liquids,benzene and toluene, are 160 mmHg and 60 mmHg respectively. At the same temperature, the vapour pressure of an equimolar solution of the two liquids, assuming the ideal solution should be
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