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The vapour pressure of a solvent decreased by 10 mm of mercury, when a non-volalite solute was added to the solvent. The mole fraction of the solute in the solution is 0.2. What should be the mole fraction of the solvent, if the decrease in the vapour pressure is to be 20 mm of mercury ?

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a

0.2

b

0.4

c

0.6

d

0.8

answer is C.

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Detailed Solution

(I) (II) temperature is constant , Po= 50mm molefraction of solvent must be 0.6

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The vapour pressure of a solvent decreased by 10 mm of mercury, when a non-volalite solute was added to the solvent. The mole fraction of the solute in the solution is 0.2. What should be the mole fraction of the solvent, if the decrease in the vapour pressure is to be 20 mm of mercury ?