Q.

The vapour pressure of water at 20oC is 17.5 mmHg. If 18 g of glucose (C6H12O6) is added to 178.2 g of water at 20oC, the vapour pressure of the resulting solution will be:

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

17.675 mmHg

b

15.750 mmHg

c

16.500 mmHg

d

17.325 mmHg

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Po-PSPS=wglu×MH2omglu×WH2o17.5-PSPS=18×18180×178.217.5-PSPS=0.01PS=17.676 mmHg.
Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon