The vapour pressures of ethanol and methanol are 44.5 mmHg and 88.7 mmHg respectively at the same temperature. An ideal solution is formed by mixing 60 g of ethanol and 40 g of methanol. The mole fraction of methanol in the vapour phase is

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0.66

0.55

0.11

0.33

answer is A.

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Detailed Solution

Mole of CH3OH=4032=1.25Mole of CH3CH2OH=6046=1.304Let CH3OH→A, C2H5OH→BXA=nAnA+nB=1.251.25+1.304=0.49∴ XB=0.51∴ PT=PAoXA+PBoXB=88.7×0.49+44.5×0.51PT=43.480+2.695=66.175∴ PA=43.48; ∴ XA=PAPT=43.4866.175=0.66

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