The variation of equilibrium constant with temperature is given below Temperature Equilibrium Constant T1=25∘CK1=10T2=100∘CK2=100 The values of ΔH0,ΔG0 at T1 and ΔG0 at T2 in kJmol−1 respectively, are close to [use R=8.314JK−1mol−1

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0.64,−5.71 and −14.29

0.64,−7.14 and −5.71

28.4,−5.71 and −14.29

28.4,−7.14 and −5.71

answer is C.

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Detailed Solution

log10⁡K2K1=ΔH02.303R1T1−1T2⇒log⁡(10)=ΔH02.303R1298−1373⇒ΔH02.303×8.314=298×37375⇒ΔH0=28377.1J/mol=28.4 kJmolat T1ΔG0=−RT1×2.303log10⁡K1=−2.303×8.314×298log1010=−5.71kJ/mol At T2ΔG0=−2.303RT2log⁡K2=−2.303×8.314×373×2=−14.29 kJmol

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