The velocity of an electron in excited state of H-atom is 1.093×106m/s. What is the circumference of this orbit?

v=vHx zn                          vH=2.186×1061.093×106=2.186×106×1nn=2 Circumference of the orbit =2πrn                                                =2π rH x n2  A0                                                  =2π.0.529x22 x10-10 m                                                          = 2×3.14×0.529×4×10−10⇒13.30×10−10m