In a vessel containing SO3, SO2 and O2 at equilibrium, some helium gas is introduced so that the total pressure increases while temperature and volume remains constant. According to Le-Chatelier principle, the dissociation of SO3
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a
increases
b
decreases
c
remains unaltered
d
changes unpredictably
answer is C.
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Detailed Solution
2SO3 ⇌ 2SO2 + O2∆H=+ve endothermic reactionInert gas doesn't show reaction with the reacting mixture it shows effect only due to its volume.At constant volume the change doesn't effect the inert gas. Thus dissociation of SO3 remains unchanged.V = constant = ∆H=0No effect on the inert gas.
In a vessel containing SO3, SO2 and O2 at equilibrium, some helium gas is introduced so that the total pressure increases while temperature and volume remains constant. According to Le-Chatelier principle, the dissociation of SO3