A vessel contains equal number of moles of helium and methane. Through a small orifice the half of gas effused out. The ratio of the number of mole of helium and methane remaining in the vessel is
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a
2 : 1
b
1 : 2
c
1 : 4
d
4 : 1
answer is B.
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Detailed Solution
Ratio of rates of diffusion of He & CH4 = 2 : 1let total moles diffused = 2+1 =3Moles of He present = 3 - 2 = 1Moles of CH4 present =3 -1 = 2Ratio = 1:2